x^2+44x-49=4x

Solution for x^2+44x-49=4x equation:

x^2+44x-49=4x

We move all terms to the left:

x^2+44x-49-(4x)=0

We add all the numbers together, and all the variables

x^2+40x-49=0

a = 1; b = 40; c = -49;
Δ = b2-4ac
Δ = 402-4·1·(-49)
Δ = 1796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1796}=\sqrt{4*449}=\sqrt{4}*\sqrt{449}=2\sqrt{449}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-2\sqrt{449}}{2*1}=\frac{-40-2\sqrt{449}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+2\sqrt{449}}{2*1}=\frac{-40+2\sqrt{449}}{2}
$